Abin contains 78 light bulbs of which four are defective. if five are randomly selected from the bin without replacement, find the probability that all five are not defective.

0.7630

Step-by-step explanation:

Probaility of defective = 4/78

Probability of NOT defective = 1 - 4/78 = 74/78

Note: probability of NOT A = 1 - probability of A

Since without replacement, we need to consider that with each turn, 1 goes down from total and we multiply all the 5 outcomes, hence:

Probability 5 not defective =

THis is the answer, 0.7630

question:

could we have options?