circle a is located at (6,5) and has a radius of 4 units. what is the equation of a line that is tangent to circle a from point c (2,8)?
a.) x = 2
b.) y = -0.75x + 9.5
c.) y = 1.33x + 1.66
d.) x = 8

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

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step-by-step explanation:

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