Here we go again lol i’m a failure and a disappointment according to my mom yayy

Hello! Your answer is y = -7/3x + 2.

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First, find the slope of the original line. The slope can be calculated by . Substitute in the points, and you get:

So now we get: slope = 3/7. We do not need the full equation of the first line, as a perpendicular line only requires the slope.

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Perpendicular lines all have a slope that is a negative reciprocal of another. For example, if one line's slope was 1/4, the line perpendicular to it would have a slope of -4.

The negative reciprocal of 3/7 is -7/3. Therefore, we know the slope of the line that we are looking for is -7/3. We can substitute this into y = mx + b.

y = -7/3x + b

Now, we are given a coordinate point. Substitute that in and solve.

-5 = -7/3 * 3 + b

-5 = -7 + b

b = 2

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Therefore, the final equation we are looking for is y = -7/3x + 2.

Hope this helps!

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°