Determine which relation is a function.
a. {(–5, 1), (–5, 0), (–2, 1), (–1, 4), (6, 2)}
b. {(–5, 1), (–2, 0), (–2, 2), (3, 4), (6, 2)}
c. {(–5, 1), (–2, 0), (–1, 1), (2, 4), (6, 3)}
d. {(–5, 3), (–2, 0), (–1, 2), (6, 4), (6, 3)}

is this part of a question or something

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v