Consider two independent populations for which the proportion of successes in the first population is p1 and the proportion of successes in the second population is p2. what alternate hypothesis would indicate that the proportion of successes p1 in the first population is larger than the proportion of successes p2 in the second population

Step-by-step explanation:

Given : Consider two independent populations for which the proportion of successes in the first population is and the proportion of successes in the second population is .

The alternative hypothesis that indicate the proportion of successes in the first population is larger than the proportion of successes in the second population:-

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

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