The point-slope form of the equation of the line that passes through (-4,-3) and (12, 1) is y-1= 1/4(x-12). what is the stadard form of the equation for this line?
x-4y = 8
x - 4y = 2
4x - y = 8
4x - y = 2

x - 4y = 8

Step-by-step explanation:

Since the Point-Slope Formula is already given to you, convert it to Slope-Intercept Form, and you do that by doing this:

y - 1 = ¼(x - 12) >> y - 1 = ¼x - 3

y - 1 = ¼x - 3

+ 1+ 1

y = ¼x - 2 >> Slope-Intercept Form

After doing this, you are ready to convert to Standard Form, and you do that by doing this:

y = ¼x - 2

-¼x -¼x

-¼x + y = -2

Now unfortunately, we do not want fractions as our coefficients, so the way to eliminate the fraction is to multiply the equation by the Multiplicative Inverse of -¼, which is -4:

-4[-¼x + y = -2] >> x - 4y = 8 → New equation without fractions

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idk

step-by-step explanation:

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