The point (1, −1) is on the terminal side of angle θ, in standard position. what are the values of sine, cosine, and tangent of θ? make sure to show all work.

Check the picture below.

Graphing the given point takes us to quadrant 4. Drop a perpendicular to the point (1, -1) and draw a line from the origin to the point. This line is the hypotenuse.

Let h = hypotenuse

(-1)^2 + (1)^2 = h^2

1 + 1 = h^2

2 = h^2

Taking the square root on both sides of the equation we get

sqrt{2} = h

In quadrant 4, only cosine is positive.

sine θ = -1/sqrt{2}

cos θ = 1/sqrt{2}

tan θ = -1/1

tan θ = -1

Did you follow?

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation: