Kx - 3y = 4
4x - 5y = 7
in the system of equations above, k is a constant
and y are variables. for what value of k will
che sistem of equations have no solution?

k=12/5=2.4

Step-by-step explanation:

1. Let's get rid of the variable y

Multiply the first equation by 5 and the second by 3

5kx-15y=20

12x-15y=60

Now subtract from equation(2)/equation(1) -> 12x-5kx=40

x(12-5k)=40 This equation is always solvable except if 12-5k=0, and this happens if k=12/5=2.4

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet