The water level in a plastic pool changed by -8 gallons each hour due to small hole in the bottom after 6 hours the pool contained 132 gallons how much water was in the pool originally

180

Step-by-step explanation:

When you multiply the about lost per hour by the amount of time, you get the amount lost total.

6*8=48

then you add that to the amount in the pool now, and you have the original amount.

i used to know but i learned it a long time ago sorry

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.