Understand subtraction as adding the opposite problem which expression is equivalent to 7\dfrac34 - \dfrac127 4 3 − 2 1 7, start fraction, 3, divided by, 4, end fraction, minus, start fraction, 1, divided by, 2, end fraction? choose 1 choose 1 (choice a) a 7\dfrac34+\left(-\dfrac12\right)7 4 3 +(− 2 1 )7, start fraction, 3, divided by, 4, end fraction, plus, left parenthesis, minus, start fraction, 1, divided by, 2, end fraction, right parenthesis (choice b) b -7\dfrac34+\left(-\dfrac12\right)−7 4 3 +(− 2 1 )minus, 7, start fraction, 3, divided by, 4, end fraction, plus, left parenthesis, minus, start fraction, 1, divided by, 2, end fraction, right parenthesis (choice c) c \dfrac12+\left(-7\dfrac34\right) 2 1 +(−7 4 3 )start fraction, 1, divided by, 2, end fraction, plus, left parenthesis, minus, 7, start fraction, 3, divided by, 4, end fraction, right parenthesis (choice d) d \dfrac12+7\dfrac34 2 1 +7 4 3

5x+2x=49

7x=49

x=7. 35 apples

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00

17.08

correct me if i am wrong.

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!