Mathematics, 21.08.2019 02:30 Sk8terkaylee
Use an appropriate taylor series to find the first four nonzero terms of an infinite series that is equal to sin(5/2).
Answers: 1
![\sin(\frac{5}{2})=\dfrac{5}{2}-\dfrac{[\frac{5}{2}]^3}{3!}+\dfrac{[\frac{5}{2}]^5}{5!}-\dfrac{[\frac{5}{2}]^7}{7!}+...](/tpl/images/0183/5049/19ac4.png)
![\dfrac{5}{2}=2.5\\\\-\dfrac{[\frac{5}{2}]^3}{3!} \approx -2.61\\\\\dfrac{[\frac{5}{2}]^5}{5!} \approx 0.81\\\\-\dfrac{[\frac{5}{2}]^7}{7!} \approx -0.12](/tpl/images/0183/5049/c6143.png)
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