Find all relative extrema and inflection points for the following function. 4) y -2x^3+24x^2+288 x-35

Relative maximum at x=12

Relative minimum at x=-4

Inflection point at x=4

Step-by-step explanation:

To find all the critical points of the function we need the first derivative of the function

According to  Fermat's theorem, it will be a critical point in y'(x)=0, then

With the test of the second derivative, we can know if the points are relative extrema or inflections.

The second derivative test says: if then x is a relative maximum, if then x is a relative minimum. So x=12 is a relative maximum and x=-4 is a relative minimum.

To find the inflection point y''(x)=0

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

i need on these three questions. find standard form equation of line perpendicular to y = (2/3)x - 8 that goes through the point

the equation of a line is -6x-2y=-18 what is the x 3 answers sep 21, 2015

finding the critical point for f(x,y)=(x^2)*y+y^3 1 answer mar 10, 2013

more results from answers.yahoo.com

step-by-step explanation: