Which quadratic function in standard form has the values a = –3.5, b = 2.7, and c = –8.2?

f(x)=-3.5x²+2.7x - 8.2

Step-by-step explanation:

We have given:

a = -3.5 , b=2.7 and c= -8.2

We have to write  quadratic function in standard form.

We know that the standard form of quadratic function is:

f(x)=ax²+bx+c

where a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

We have the values a= -3.5 , b = 2.7 and c = -8.2

Substitute the values  in the standard form:

f(x)=-3.5x²+2.7x - 8.2

Therefore the answer is: f(x)=-3.5x²+2.7x - 8.2

d

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)