Find all the zeros of the polynomial function p(x) x^4-4x^3 -5x^2+38x- 30

The zeros of the polynomial function are 1, -3, 3+i and 3-i.

Step-by-step explanation:

The given function is

We can find a zero of the given function by hit and trial method.

Substitute x=1 in the given function.

The value of function is 0 at x=1 it means (x-1) is a factor of given function.

Substitute x=-3 in the given function.

The value of function is 0 at x=-3 it means (x+3) is a factor of given function.

Divide the given function by , to get remaining factors.

So, the factor form of given function is

Quadratic formula: If a quadratic equation is , then

Using quadratic formula find the zeroes of .

Therefore the zeros of the polynomial function are 1, -3, 3+i and 3-i.

it’s supposed to be -4+45=41

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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