Sales prices of baseball cards from the 1960s are known topossess a skewed-right distribution with a mean sale price of $5.25and a standard deviation of $2.80. suppose a random sample of 100cards from the 1960s is selected. describe the samplingdistribution for the sample mean sale price of the selectedcards. a. skewed-right with a mean of $5.25 and a standard error of$2.80b. normal with a mean of $5.25 and a standard error of$0.28c. skewed-right with a mean of $5.25 and a standard error of$0.28d. normal with a mean of $5.25 and a standard error of$2.80

c. Skewed-right with a mean of $5.25 and a standard error of$0.28

Step-by-step explanation:

As we have given that Sales prices of baseball cards have a right-skewed distribution with a mean $5.25 and a standard deviation is $2.80.

Now, We know that if standard deviation = σ

then, standard error =

As, we have standard deviation = $2.80

then standard error will be

⇒ Standard error = $0.28

Hence, Option (c) is the correct option.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7