In the formula a(t) = a0ekt, a(t) is the amount of radioactive material remaining from an initial amount a0 at a given time t and k is a negative constant determined by the nature of the material. a certain radioactive isotope decays at a rate of 0.1% annually. determine the half-life of this isotope, to the nearest year.

 693 years

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

k = rate constant

t = time taken for decomposition = 1

= Initial amount of the reactant

= amount of the reactant left =

for half life :

Putting in the values , we get

Thus half life of this isotope, to the nearest year is 693.

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

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