4. you are traveling to chicago for a job interview. you leave toledo, ohio, at 5: 45 a. m. and arrive in elkhart, indiana, at 8: 15 a. m.. the distance from toledo to elkhart is 136 miles; the distance from toledo to chicago is 244 miles. the speed limit is 65 mph. what is the minimum speed you must maintain in order to arrive in chicago before 10: 30 a. m.? oa. 45 mph ob. 48 mph oc. 50 mph od. 58 mph oe. 60 mph

48 mph

Step-by-step explanation:

First we need to find the distance from Elkhart to Chicago. Toledo to Elkhart is 136 miles and Toledo to Chicago 244 miles.

So the distance from Elkhart to Chicago can be calculated, since Chicago is farther from Toledo than Elkhart, as: distance(Toledo to Chicago) - distance(Toledo to Elkhart). These distances are given in the problem, so the distance from Elkhat to Chicago is: 244 miles - 136 miles = 108 miles.

This problem basically wants to know the slowest you can be yet still ariving on time. If you are the minimum speed, you will arrive in Chicago exactly at 10:30 A.M. So you have 2 hours and 15 minutes(10:30 A.M - 8.15A.M.) to drive 108 miles.

15 minutes is a fourth of a hour, so you have 2.25hours to go through 108 miles.

The minimum speed you must maintain is 108mph/2.25h = 48mph.

the correct answer is you spend $55.78 more in a brand store that buy ing in a normal store.

step-by-step explanation:

brand = spend   $ 135.85 total

store = spend $80.07 total