Can someone explain to me how to do problems like x - 2/5 = 7
and x + 4/5 = 11? i don't really need the answers, i just can't understand : /// idk how to find the value of x s yea

x=37/5 ; x=51/5

Step-by-step explanation:

x -  2/5= 7

here,

x-2/5

LCM of denominators(1 &5)=5

5 (LCM of denominators) divided by the denominator of x(which is 1)= 5/1 =5

then,

5 multiply with numerator of x (which is x) = 5x

again,

5 (LCM of denominators) divided by the denominator of 2/5(which is 5) = 5/5=1

then,

1 multiply with numerator of 2/5 (which is 2)= 1 x 2 =2

so,

the fraction is,

(5x-2)/7

which is = 7

so,

(5x-2)=35           [multiplied by 5 on both site ]

5x=35+2             [add 2 on both site]

5x=37

x=37/5              [divided by 5 on both site]

similarly,

x + 4/5 = 11

=>(5x+4)/5=11

=>5x+4=55          [multiplied by 5 on both site ]  

=>5x=55-4           [subtraction by 4 on both site]

=>5x=51

=>x=51/5                [divided by 5 on both site]

step-by-step explanation:

compare

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse