Find the equation of the line using the point-slope formula. write the final equation using the slope-intercept form. perpendicular to 8y = x − 4 and passes through the point (−2, 1)

point-slope form;

(y - 1) = -8(x+2)

slope-intercept form;

y = -8x - 15

Step-by-step explanation:

The first step is to determine the slope of the given line;

8y = x − 4

y = 1/8(x) - 1/2 After dividing both sides by 8

The slope of the line is thus 1/8, the coefficient of x when the equation is written in slope-intercept form.

The required line is perpendicular to this given line which implies that the product of the slopes will be equal to -1. Let the slope of the required line be m;

m * 1/8 = -1

m = -8

The slope of the required line is thus -8. Using the given point,  (−2, 1), the equation of this line in point-slope form becomes;

(y - 1) = -8(x - -2)

(y - 1) = -8(x+2)

We make y the subject of the formula;

y = -8x - 16 + 1

y = -8x - 15

This is the slope-intercept form of the equation of the line.

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo