Two times the greater of consecutive integers is 9 less than three times the lesser integer. what are the integers?

The integers are 11 and 12.

Step-by-step explanation:

Let x be the greater integer, then the lesser is x - 1, so:

2x = 3(x -1) - 9       Distribute the 3:

2x = 3x - 3 - 9       Subtract 3x from both sides:

-x = -3 - 9

-x = -12

x = 12.

answer: 4 (:

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)