In one pocket, i have two quarters; in the other, i have a quarter and a nickel. my toddler reaches into one of my pockets and grabs a coin. assume that she picks the pocket and the coin randomly, and that the chance she reaches into each pocket is 50%, and the chance that she pulls out each of the two coins in each pocket is the same. what is the conditional probability that the second coin in the pocket she reaches into is a quarter, given that the coin she pulls out is a quarter?

You have a 50% probability of picking a pocket.

Each pockets probability of picking a quarter:

The pocket with two quarters you have a 100% chance of picking one. In the other pocket you have a 50% chance of picking a quarter.

0.5(1) + 0.5(0.5) = 0.75

The probability of picking a quarter at first becomes 3/4.

The probability of picking a a second quarter, becomes 100% in the pocket that had 2 and 0% in the pocket that had one.

0.5(1) + 0.5(0) = 0.5

The probability of picking a second quarter becomes 1/2.

The probability of picking a second quarter given the first one was a quarter becomes:

1/2 / 3/4 = 2/3 probability.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

hello! just here for points! though i wish i knew!