Atechnician randomly sampled repair logs for computers at a university. he wanted to find out how many times the computers were repaired. the proportion of computers that were repaired more than three times in the last two years was 0.24, with a margin of error of 0.03. construct a confidence interval for the proportion of university computers that were repaired more than three times in the last two years.

Step-by-step explanation:

The confidence interval estimate for the population proportion is given by :-

, where is the sample proportion of success and ME  is the margin of error.

Given : The proportion of computers that were repaired more than three times in the last two years :

Margin of error :

Now, the confidence interval estimate for the population mean will be :-

Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution =  

168

step-by-step explanation:

first off, we know that he drove 3.5 hours at a rate of 48 mph.

knowing that, we want to see how many miles he drove all-together.

in this case, we can just multiply 48 by 3.5.

48 * 3.5 = 168

nope lol

step-by-step explanation: