F. a bag contains 3 red, 4 blue, 3 green, and 5 yellow marbles. what is the probability of
picking two green marbles in a row, without replacing the first marble?

Step-by-step explanation:

you first add up the marbles together. 3 + 4 + 3 +.5 = 15. Then you take the amount of green marbles their are, and make a fraction: 3/15. Then you remove one without putting it back, which is green, so you have 1 less total and one less green marbles, and you turn that into a fraction: 2/14.

First Pick: 3/15 chance of getting green

Second Pick: 2/14 chance of getting green

Then. You divide the first number by the second one.

3 / 15 = 0.2

2 / 14 = 0.142

Then to turn into percentage you move the decimal over two spots and drop the 0 and add a percentage sign:

20%

14.2% (Round Up Percentage) 15%

Which means that:

20% Probabiltiy for first pick

15% Probability for second pick

  I hope this helps. If it is incorrect, comment that, and I will see what U messed up. I hope I helped. :D

45

step-by-step explanation:

a

step-by-step explanation: