The popularity rate of a political candidate is 52%. if 18 citizens are randomly selected, what is the probability that more than 12 in the sample are in favor of this candidate?

Answer)

The probability is 0.068

Explanation)

We shall use the binomial distribution to evaluate the problem

The probability that an event X occurs exactly 'r' times in 'n' trails is given by

where 'p' is the probability of success of the event E

In the given case

p = 0.52

n = 18

Thus the probability that more than 12 people like the political candidate is

the probability that  13 or 14 or 15 or 16 or 17 or 18 people like the politician  thus is  given by values of 'r' belonging to the set {13,14,15,16,17,18}

Applying values we get

Thus P(E) = 0.068

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it