Hugo averages 58 words per minute on a typing test with a standard deviation of 11 words per minute. suppose hugo's words per minute on a typing test are normally distributed. let x= the number of words per minute on a typing test. then, x∼n(58,11). suppose hugo types 74 words per minute in a typing test on wednesday. the z-score when x=74 is this z-score tells you that x=74 is standard deviations to the (right/left) of the mean,

The number of words that Hugo wrote in the test of Wednesday (74) is at a distance of 1.4545 standard deviations (11) to the right of his mean (58)

Step-by-step explanation:

A normal random variable with mean Mu = 58 and standard deviation sd = 11 is standardized with the transformation (z-score):

Z = (X - Mu) / sd = (X - 58) / 11

For a value of 74 for X, Z = (74 - 58) / 11 = 1.4545 > 0.

The z-score when X = 74 is 1.4545 > 0

This means that the number of words that Hugo wrote in the test of Wednesday (74) is at a distance of 1.4545 standard deviations (11) to the right of his average (58)

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75