Na survey of 1227 people, 828 people said they voted in a recent presidential election. voting records show that 65% of eligible voters actually did vote. given that 65% of eligible voters actually did vote. a) find the probability that among 1227 randomly selected voters, at least 828 actually did vote. b) what do the results from part (a) suggest?

0.0344

Step-by-step explanation:

For binomial distribution :-

, where p is the proportion of success in each trial and n is the sample size.

Given : Sample size : n=1227

The proportion of people said they voted in a recent presidential election :p=0.95

Then,

Let X be the binomial variable.

z-score :

For x= 828

Then,  probability that among 1227 randomly selected voters, at least 828 actually did vote is given by :-

Hence,  the probability that among 1227 randomly selected voters, at least 828 actually did vote= 0.0344

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.