For a language test with normally distriuted scores, the mean was 70 and the standard deviation was 10. approximately what percentage of test takers scored a 60 or above?

84.13%

Step-by-step explanation:

Given : The scores in a a language test with normally distributed.

Mean :

Standard deviation:

Let x be the random variable that represents the scores of students.

Formula for z-score:

For x= 60 , we have

The probability f test takers scored a 60 or above :-

Hence, the percentage of test takers scored a 60 or above = 84.13%

because they could drop even lower..

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!