Find the quadratic equation for y=x^2+6x-7

x = -1 or x = 7

Step-by-step explanation:

From my understanding, y will be zero and you have to find the value of x.

Step 1: Middle term break

y = x² + 6x - 7

x² + 6x - 7 = 0

x² - 7x + x - 7 = 0

Step 2: Solve

x(x-7) + 1(x-7) = 0

(x+1) (x-7) = 0

x = -1 or x = 7

Therefore, the value of x is either -1 or 7.

!!

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.