Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) write out the first 5 terms of this sequence,

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by

To find : Write out the first 5 terms of this sequence ?

Solution :

and

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

For n=2,

For n=3,

For n=4,

For n=5,

The first 5 terms of the sequence is 2,7,15,26,40.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?