Asimple random sample of 25 filtered 100 mm cigarettes is obtained, and the tar content of each cigarette is measured. the sample has a mean of 19.6 mg and a standard deviation of 3.68 mg. use a 0.05 significance level to test the claim that the mean tar content of filtered 100 mm cigarettes is less than 21.1 mg, which is the mean for unfiltered king size cigarettes. what do the results suggest, if anything, about the effectiveness of the filters?

There is sufficient statistical evidence in the sample to state that the average tar content in filter cigarettes is less than 21.1.

Step-by-step explanation:

To solve this problem, we run a hypothesis test about the population mean. Consider the average tar content in filter cigarettes.

Mean in the null hypothesis (Mo) =

Sample size (n) = 25

Sample mean (X) = 19.6

Sample standard deviation (S) = 3.68

Significance level = 0.05

H0: Mo = 21.1

Ha: Mo = <21.1

Test statistic =

Left critical T value (for 0.05) = -1.7109

Calculated statistic = = -2.0380

Since, the value of the test statistic is less than the value of the calculated statistic, the null hypothesis is rejected. There is sufficient statistical evidence in the sample to state that the average tar content in filter cigarettes is less than 21.1.

answer: 230 miles ( vote ! )

step-by-step explanation:

180.39 minus 17.99 equals 162.4

then divide 162.4 by .80 to get 230

(2,20) means that the 2 is 2 hours and 20 is 20$. so there both 20$ for 2 hours only the same price. like it says. so, the dunk tank and the bounce house are the same price (20$) for the same amount of time (2 hours).

hope i