Which is not an equation of the line going through (3.-6) and (1, 2)?
o a. y+6=-4(x-3)
o b. y-1 =-4(x - 2)
o c. y-2=-4(x-1)
o d. y=-4x+6

B

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, - 6) and (x₂, y₂ ) = (1, 2)

m = = = - 4

Using m = - 4 and (a, b) = (3, - 6), then

y - (- 6) = - 4(x - 3), that is

y + 6 = - 4(x - 3) → equation A on list

Using m = - 4 and (a, b) = (1, 2), then

y - 2 = - 4(x - 1) → equation C on list

Distribute and simplify

y - 2 = - 4x + 4 ( add 2 to both sides )

y = - 4x + 6 → equation D on list

The above are 3 valid equations of the line

Thus B is not the equation of the line.

the answer is c.

step-by-step explanation:

statement #3: proof- ang is congruent to ang ecd : angles are congruent.  

step-by-step explanation:

1: the missing angles in statement #3  

a.) acb  

reason- the reason why the answer is acb is because angle ecd and angle acb are both the same size *that's what the word congruent means this is really simple.  

2: the missing word in reason #3  

c.) vertical  

reason- the reason why the answer is vertical is because the angles in that diagram on figure 2 is slanted, which is vertical, and the e and a both lay on vertical lines. along with the other's, but e and a are the 2 main points you want to focus on. and c is kind of like your starting point, because c is for both angles, not just one.  

i hope that was and understanding.