Aball is thrown vertically in the air with a velocity of 95 ft/s. what time in seconds is the ball at a height of 120ft. round to the nearest tenth of a second .

On the way up, 1.8 seconds and on the way down 4.1 seconds.

Step-by-step explanation:

Use the  motion under gravity  equation s = ut + 0.5gt^2 where u = initial velocity, s = the height, t = time and g = acceleration due to gravity ( 32 fts-2).

So 120 = 95t + 0.5(-32)t^2

-16t^2 + 95t - 120 = 0

Solving this using the quadratic formula:

t = [-95 +/- √(95^2 - 4 * -16*-120)] / -32

t = 1.823, 4.1148.

The first value refers to the upward journey and the second to the downward journey.

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct

answer: asdfghjkl,mnbv

step-by-step explanation: