Question 12 1 pts if the population of a country is reported in the year 1990 as 471.56 million and in the year 2000 as 492.53 million, what will the population be in the year 2015 (round your answer to the nearest hundredths)? 767.15 million 831.31 million 526.39 million 275.18 million

  526.39 million

Step-by-step explanation:

The exponential equation can be written as ...

  p(t) = 471.56(492.53/471.56)^(t/10)

Then p(25) ≈ 525.75 . . . . million

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The closest answer choice is 526.39 million.

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Comment on the answer choice

Reverse-engineering the answer, we find it was computed using the exponential equation ...

  p(t) = 471.56e^(0.0044t)

  p(25) = 471.56·1.116278 ≈ 526.39

The k factor in the exponent is inappropriately rounded from 0.004350903. You cannot use a 2-significant-figure constant to arrive at an accurate 5-significant-figure answer.

the arc length is found by finding the circumference of the full circle (2xpixradius) and then dividing by 4 to find just one quarter of the circle (90 degrees).

4y - 6 + y^2 - 9 = y^2 + 4y - 15

y^2 term

terms

- terms

total of 3 terms when simplified

step-by-step explanation: