If the equation of a circle is (x - 2)2+(-6)2 = 4, the center is point (2,6).
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If you meant to write (x-2)^2 + (y-6)^2 = 4, then the center is (2,6). The statement would be true.

This is because the general form (x-h)^2 + (y-k)^2 = r^2 describes a circle centered at (h,k) with radius r. In this case, h = 2, k = 6, r = 2. Note how r^2 = 4 so r^2 = 2^2 leads to r = 2.

the answer on e2020 is

10

4/5

3/5

4/3

step-by-step explanation:

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: