![y=\frac{-3}{5}x+3](/tpl/images/0213/5989/0481e.png)
I don't see this in any of your choices.
Please be sure the problem and choices are as you want them to be seen by others. Thanks kindly.
I do hope my answer is helpful.
Step-by-step explanation:
![3x+5y=15](/tpl/images/0213/5989/74cf4.png)
We want to get the term that contains
by itself.
This means we want to get
by itself first.
To do this I need to get rid of the plus
on that side.
I will do the inverse operation of that; I will subtract 3x on both sides.
![3x+5y=15](/tpl/images/0213/5989/74cf4.png)
-3x -3x
![5y=15-3x](/tpl/images/0213/5989/ec755.png)
![5y=+15-3x](/tpl/images/0213/5989/c19b3.png)
since addition is commutative.
Now we have the 5y term by itself. We want the factor y in 5y by itself.
To undo multiplication you must divide. We will divide both sides by 5:
![5y=-3x+15](/tpl/images/0213/5989/c751a.png)
------------------------------
5
![\frac{5y}{5}=\frac{-3x+15}{5}](/tpl/images/0213/5989/310c5.png)
![y=\frac{-3x}{5}+\frac{15}{5}](/tpl/images/0213/5989/de727.png)
![y=\frac{-3}{5}x+3](/tpl/images/0213/5989/0481e.png)