Find the point on the x-axis that is equidistant from the points (−3,−1) and (1,6)

well, we'll be using the distance formula twice here.

that point, is on the x-axis, what's the value of "y" at the x-axis?  well y = 0, since it's way down at the 0 level, so the point must be (x , 0).

the distance then from (x,0) to (-3,-1) is the same distance as from (x,0) to 1,6).

80%

step-by-step explanation: