The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. find the length and width of the garden

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

subtracting 100 from both sides

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

Solving first

Solving second one

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

b) the dogs need to shift their focus to human scent.

this is not the answer this is just a question. is this middle school math?

step-by-step explanation: