Y-3=-2/3(x+3) for y
can someone me pls im bad at fractions

y-3=-2/3(x+3)

Mutiply the bracket by -2/3

(-2/3)(x)= -2/3x

(-2/3)(3)- cross out 3 and 3 , divide by 3 then becomes -2*1= -2

y-3= -2/3x-2

Move -3 to the other side

Sign changes from -3 to +3

y-3+3= -2/3x-2+3

y= -2/3x-2+3

y= -2/3x+1

y= -2/3x+1

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.