In a right triangle abc, right angled at c, p and q are points on the sides ca and cb respectively which divide these sides in the ratio 2: 1. prove that:
(i) 9 aq^2 = 9 ac^2 + 4 bc^2
(ii)9 bp^2 = 9 bc^2 + 4 ac^2
(iii) 9 (aq^2 + bp^2) = 13 ab^2

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

step-by-step explanation: s

step-by-step explanation:

x-intercept:

(

−

1

+

√

7

,

0

)

,

(

−

1

−

√

7

,

0

)

y-intercept:

(

0

,

−

6

)