In a laboratory population of drosophila, all the males are xsy. among the females, 15% are xixi, 50% are xixs, and 35% are xsxs. assuming random mating, what proportion of male flies in the next generation will be xiy?

20 % from the next generation will be male XiY

Step-by-step explanation:

females have are XX always and males are XY, so when cross a woman an a man the probability of have a male is 50 %

XX - XY

⇒XX

⇒XY

⇒XX

⇒XY

P (female) = = 0.5 = 50 %

P (male) = = 0.5 = 50 %

Then the probability oh have a male XiY is dependent first oh have a male and second that the male will be XiY

The probability of a dependent probability is the product of the probabilities

P (XiY) = P (male) * P (male wit the character Xi)

P (male wit the character Xi) = P (of be XiY from the amount of males from the cross XiXi with XsY) * P (XiXi) + P (of be XiY from the amount of males from the cross XiXs with XsY) * P (XiXs) + P (of be XiY from the amount of males from the cross XsXs with XsY) * P (XsXs)

1. XiXi - XsY

⇒ XiXs (female)

⇒XiXs (female)

⇒XiY (male)

⇒XiY (male)

From the 2 male, both can be XiY

P (of be XiY from the amount of males from the cross XiXi with XsY) =

2. XiXs - XsY

⇒ XiXs (female)

⇒XsXs (female)

⇒XiY (male)

⇒XsY (male)

From the 2 male, one can be XiY

P (of be XiY from the amount of males from the cross XiXs with XsY) =

3. XsXs - XsY

⇒ XsXs (female)

⇒XsXs (female)

⇒XsY (male)

⇒XsY (male)

From the 2 male,any of them can be XiY

P (of be XiY from the amount of males from the cross XsXs with XsY) =

P (male wit the character Xi) = P (of be XiY from the amount of males from the cross XiXi with XsY) * P (XiXi) + P (of be XiY from the amount of males from the cross XiXs with XsY) * P (XiXs) + P (of be XiY from the amount of males from the cross XsXs with XsY) * P (XsXs)

P (of be XiY from the amount of males from the cross XiXi with XsY) = 1

P (of be XiY from the amount of males from the cross XiXs with XsY) =

P (of be XiY from the amount of males from the cross XsXs with XsY) = 0

P (male wit the character Xi) = =

P (XiY) = P (male) * P (male wit the character Xi)

P(XiY) =

20 % from the next generation will be male XiY

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

use formula for the circle a=3.14

step-by-step explanation: