Suppose you just received a shipment of seven televisions. four of the televisions are defective. if two televisions are randomly selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not work?

The probability that hat both televisions work= 0.1837

The probability at least one of the two televisions does not work=0.8163

Step-by-step explanation:

Given : Total televisions = 7

Defective televisions = 4

The proportion of defective sets :  

Number of televisions selected = 2

Using binomial probability formula :

The probability that hat both televisions work. :_

The probability at least one of the two televisions does not work:-

the answer is d. (1.2, -4.7) on edgn

hope this !

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)