Terry and tao are canoeing on a lake that is 2000 meters across from the west side of the lake to the east side. terry rows at 60 meters per minute and tao rows at 40 meters per minute. terry starts rowing at 2 pm from the west end of the lake, and tao starts rowing from the east end of the lake at 2: 05 pm. if they always row directly towards each other, at what time will the two meet?

2:22 PM

Step-by-step explanation:

Given

Terry rows at 60 meters per minute

and Tao rows 40 meters per minute

Terry starts 5 mins earlier than Tao

so additional distance covered by him is

so net distance between them is 2000-300=1700 m

suppose they meet after t mins

thus

let distance travel by Terry is x m so Tao will travel 1700-x m

Solving we get

x=1020 m

so they will meet at

thus they meet at 2:22 PM

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

happy to

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