Acircle is centered at o(0,0) and has a radius of \sqrt{38} where does the point (6,1) lie

the answer will be the last one

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

their is no graph showing

step-by-step explanation:

the formula of a slope:

we have the points (-2, 7) and (2, 3). substitute: