Arectangular painting measures 12 inches by 14 inches and contains a frame of uniform width around the four edges. the perimeter of the rectangle formed by the painting and its frame is 60 inches. determine the width of the frame.

answer: 60

step-by-step explanation:

1/2a + (2/3×30)   = 50

1/2a + 20 = 50

1/2a = 30

a = 60

is there any photos or whatever?

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

c-   36

taxicab circle radius 9 has 4(9) = 36 points