Need asap! the distance between cities p and q is 210 km. car a leaves p to q while car b leaves q to p at the same time and using the same route. cars a and b meet after 1.2 hours after traveling. given both cars travel at constant speeds where car a is moves 10 km/h faster than car b. calculate the speed, in km/h, of car a.

step-by-step explanation:

$12. that is my answer.

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).