The probability that a randomly selected person has high blood pressure (the event h) is p(h) = 0.3 and the probability that a randomly selected person is a runner (the event r) is p(r) = 0.5. the probability that a randomly selected person has high blood pressure and is a runner is 0.2. find the probability that a randomly selected person is a runner, given that he has high blood pressure.

2/3 = 0,67

Step-by-step explanation: We have P(H) = 0,3 and P(R) = 0,5.

P(High blood pressure and runner) = P(H∩R) = 0,2

The problem asks for P(runner, given he has high blood pressure) = P(R|H). This conditional probability is given by the formula:

P(A|B) = P(A∩B)

               P(B)      

In this case, P(R|H) = P(H∩R) = 0,2 = 2 = 0,67

                                   P(H)        0,3    3  

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).