Can anybody me with these 3 questions and you

1. 4 / 1/3

pretend that 4 has a denominator which is 1.

flip over the second fraction

4*3= 12

2. 3/8 +7/2

find the common denominator for 7/2 which is 8. multiply by 4 for 7/2. (7)(4)/(2)(4)=28/8

3/8+28/8=31/8

31/8 or 3 7/8

3. 3 1/2 +7/4

find the common denominator for 3 1/2 which is 4. multiply by 2 for the numerator and denominator. (1)(2)/(2)(2)=2/4

3 2/4 +7/4

make 3 2/4 into an improper fraction. mutiply the whole number with the denominator. 3*4=12. add 12 with the numerator. 12+2=14, 3 2/4=14/4

14/4+7/4=21/4

21/4 or 5 1/4

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.