How many positive factors of 200 are divisible by 4?
a. 2
b. 5
c. 6
d. 8
twice the sum of the prime factors of 35 is k. what is the value of k-4?
a. 12
b. 14
c. 16
d. 20
in the set of consecutive integers from 16 to 45, inclusive, there are 2 integers that are multiples of both 4 and 5. how many integers in this set are multiples of neither 4 nor 5?
a. 17
b. 18
c. 19
d. 20
how many positive even factors of 120 are greater than 1 and less than 40?
a. 8
b. 9
c. 10
d. 11
answer all questions, you!

C. 6, D. 20, B. 18, B. 9

Step-by-step explanation:

#1. Factors of 200 are 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100 & 200, of which 6 are divisible by 4 (4, 8, 20, 40, 100 & 200)

#2. Prime factors of 35 are 7 & 5, twice the sum of these factors, k = 24. k-4 = 20

#3. Non-multiples of 4 nor 5 between 16 and 45 are 17, 18, 19, 21, 22, 23, 26, 27, 29, 31, 33, 34, 37, 38, 39, 41, 42 & 43...thus 18 non-multiples

#4. Even factors of 120 greater than 1 and less than 40 are 2, 4, 6, 8, 10, 12, 20, 24 & 30...thus there are 9 even factors

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

54.864 meters

step-by-step explanation: