Tanya bought five adult tickets and one children's tickets to a movie for $37.10.li bought three adult tickets and five children's tickets for $38.10. find the cost of one adult ticket and the cost of one children's ticket.

Step-by-step explanation:

Let a and c represent the costs of 1 adult and 1 children's ticket, respectively. Then the two purchases can be written as ...

  5a +c = 37.10

  3a +5c = 38.10

Solving this system of equations will give the ticket prices.

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Subtracting the second equation from 5 times the first gives ...

  5(5a +c) -(3a +5c) = 5(37.10) -(38.10)

  22a = 147.40

  a = 6.70

The first equation is useful for finding the value of c:

  5(6.70) +c = 37.10

  c = 3.60 . . . . subtract 33.50

The cost of one adult ticket is $6.70; the cost of one children's ticket is $3.60.

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The two equations can also be solve quickly using a graphing program.

mx+89b(-98)nb

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."