In a simulation exercise, regression model (1.1) applies with f30 = 100, f31 = 20, and a 2 = 25. an observation on y will be made for x = 5.
a. can you state the exact probability that y will fall between 195 and 205? explain.

We can not state the exact probability that y will fall between 195 and 205

Step-by-step explanation:

* Lets explain how to solve the problem

- Regression model applies with f(30) = 100 and f(31) = 20

- The variance = 25

- An observation on y will be made for x = 5

- Suppose that the regression model is

∵

∵

∵ x = 5

∴ Y = 100 + 20(5) = 100 + 100 = 200

∴ Y = 200

- But the regression model is without error term

∵ We do not know the probability distribution of y for each value

  of x we only know the value of y at one value of x

∵ We know that the mean of distribution is 100 + 20x

∵ We know the variance of distribution is 25

∵ We don not know the shape of the distribution

- We can not  find the exact value of probability of y without the

  Normal error and the regression model must be

  to know that it has a normal distribution

∴ We can not calculate the exact value of probability of y

∴ We can not state the exact probability that y will fall between 195

  and 205

attachment?

step-by-step explanation:

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.